ASCII to Binary Converter

Syntax:

ascii.toBinary(stringoftext)
ascii.fromBinary(stringofbinary)

columna1, on 19 August 2014 - 06:14 AM said:

This is nice for a start. Take a look into the functions 'string.byte' and 'string.char' and look into number to binary conversion functions. That way you can convert back an forth without that big table.

theoriginalbit, on 19 August 2014 - 09:17 AM said:

more precisely take a look into tonumber and how you can provide a base for it. it would reduce your fromBinary function to a single line.

Dragon53535, on 19 August 2014 - 07:19 PM said:

I can see that line, return string.char(tonumber(input,2)) however that would still require acutually me calling the toTable function first, and then converting it inside the toTable and just returning the same value string.concat'd so in essence i would really just have to return toTable(string,8) and then it would be fine.

function fromBinary( str )
  assert( #str % 8 == 0, "malformed binary sequence" )
  local out = ""
  for i = 1, #str, 8 do
    local byte = str:sub(i, i + 8)
    local char = tonumber(byte, 2)
    out = out..string.char(char)
  end
  return out
end

if not condition then
  error("message")
end

if #str % 8 ~= 0 then
  error("malformed binary sequence", 2)
end

digits = {}
for i=0,9 do digits[i] = strchar(strbyte('0')+i) end
for i=10,36 do digits[i] = strchar(strbyte('A')+i-10) end
function numberstring(number, base)
   local s = ""
   repeat
	  local remainder = mod(number,base)
	  s = digits[remainder]..s
	  number = (number-remainder)/base
   until number==0
   return s
end

str = numberstring(10,2)
str = string.repeat("0",8-#str)..str
--this would return "00001010"


--you can also build this into the function itself like so:
return string.repeat("0",8#s)..s

for i = 1,#str do
  table.insert(table,tonumber(str:sub(i,i)))
end

columna1, on 22 August 2014 - 05:40 AM said:

str = numberstring(10,2)
str = string.repeat("0",8-#str)..str
--this would return "00001010"
--you can also build this into the function itself like so:
return string.repeat("0",8#s)..s

str = string.format("%08d", numberString(10,2))
--# other examples
print(string.format("%08d", "01010")) --# outputs as 00001010
print(string.format("%08d", "11")) --# outputs as 00000011
print(string.format("%08d", "11000011")) --# outputs as 11000011
print(string.format("%08d", "100101101")) --# outputs as 100101101

theoriginalbit, on 20 August 2014 - 11:27 AM said:

–snip–
Actually if you want to do entire strings it would be longer than a line… Example expanded for readability.

function fromBinary( str )
  assert( #str % 8 == 0, "malformed binary sequence" )
  local out = ""
  for i = 1, #str, 8 do
	local byte = str:sub(i, i + 8)
	local char = tonumber(byte, 2)
	out = out..string.char(char)
  end
  return out
end

columna1, on 22 August 2014 - 05:40 AM said:

I like the function you created to convert numbers to binary, very creative. However there are functions that do this quite well and (just as a tip) you would do well to learn some in order to cut down lines and add flexibility. Here is one:

digits = {} --# Note from Dragon: These three lines are useless as i can just set s to be remainder..s and have it work for binary, other bases, not so much, but i'm using it for binary.
for i=0,9 do digits[i] = strchar(strbyte('0')+i) end
for i=10,36 do digits[i] = strchar(strbyte('A')+i-10) end
function numberstring(number, base)
   local s = ""
   repeat
	  local remainder = mod(number,base)
	  s = digits[remainder]..s
	  number = (number-remainder)/base
   until number==0
   return s
end

This will convert to many bases and is used like numberstring(10,2) which will output "1010" which if needed you can append the needed ammount of 0s onto the end like so

str = numberstring(10,2)
str = string.repeat("0",8-#str)..str
--this would return "00001010"


--you can also build this into the function itself like so:
return string.repeat("0",8#s)..s

Remember these are just suggestions and you don't have to implement them if you don't want. ;)/>
I like to learn new things so I gave you this, so have fun so please feel free to play around and edit it as you please!

theoriginalbit, on 22 August 2014 - 06:10 AM said:

-snip-
alternatively, using some Lua magic we can do this

str = string.format("%08d", numberString(10,2))
--snip--

the magic here is that even though %d specifies number, Lua is able to treat the string as a number as it only contains numbers.