28 posts
Posted 22 February 2015 - 12:59 AM
Coded this in a hurry, so don't expect much from it. (Meaning I didn't have enough time to add leap years in the calculation)
Also, it would be nice if you were to give me credit if you're going to use this piece of code because it took me awhile to make this calculation.
Also, it would be nice if you were to give me credit if you're going to use this piece of code because it took me awhile to make this calculation.
Spoiler
format_day = function()
days_in_months = {31,28,31,30,31,30,31,31,30,31,30,31}
months = {31,59,90,120,151,181,212,243,273,304,334,365}
sMonths = {"January","February","March","April","May","June","July","August","September","October","November","December"}
_day = os.day()
_y = math.floor(_day/365)
d = _day - (365*_y)
if _day % 365 == 0 then _y = _y - 1 end
for i,v in pairs(months) do
if (d - v) < 0 then
_m = i
_d = days_in_months[i] - math.abs(d - v)
if _d == 0 then
if _m == 1 then _m = 12 else _m = _m - 1 end
_d = days_in_months[_m]
end
break
end
end
_m = sMonths[_m]
return _m.." ".._d..", ".._y
end
