1 posts
Posted 11 December 2012 - 10:16 AM
Is there a better way of getting the base of a filepath than this?
string.reverse(string.sub(string.reverse(filepath),string.len(fs.getName(filepath)+1)
Thanks is advance!
302 posts
Posted 11 December 2012 - 11:08 AM
This:
---returns directory from filepath @s
--according to CC, the root directory is '/', and here it's the same
function getDir(s)
return string.match(s,'^(.*)/') or '/'
end
1604 posts
Posted 11 December 2012 - 11:56 AM
Or this:
function getDir(path)
return string.sub(path, 1, #path - #fs.getName(path))
end