http.listen

syntax:

local url, data = http.listen(60) -- timeout = 60 seconds
url, data = http.listen() -- no timeout

description:
similar to rednet.receive, but is receiving via http instead of rednet
listens for timeout seconds if given, or until terminated if not given
returns a string of the URL and a file buffer of data received

So do you mean this as it listens for 60 seconds and then pulls the website data after the 60 seconds? or do you want it to do something like this? Or am I misunderstanding completely?

http.request( url )
local timeout = os.startTimer( 60 )
while true do
  local event = { os.pullEvent() }

  if event[1] == "http_success" then
	print( "Got response" )
	return
  elseif event[1] == "http_failure" then
	print( "No response from server" )
	error()
  elseif event[1] == "timer" and event[2] == timeout then
	print( "A timeout has occurred with no response from the server." )
	error()
  end
end

basically, it listens for any server on the internet to post data to it, then returns the url and postdata
timeout is when it fails and returns the the rest of the code

i am trying to implement ComputerCraft-side servers to pass information back and forth between the internet and rednet.
i got this idea from working with javascript:

var http = require("http"), server;
server = http.createServer(function(request, response) {
… server code …
});
server.listen(8080)

note: the 8080 in this case is the port the server "listens" to, not the timeout

You can easily write a funciton that does this for you.

Actually, TheOriginalBit posted one in this thread. :P/>

Cranium, on 15 January 2013 - 01:30 PM said:

You can easily write a funciton that does this for you.

there is no way to receive without specifying a URL with the given functions

http.listen does not specify which URL it is listening to

Orwell, on 15 January 2013 - 01:41 PM said:

Actually, TheOriginalBit posted one in this thread. :P/>

again, that requires a URL to be specified

tesla1889, on 15 January 2013 - 01:50 PM said:

Cranium, on 15 January 2013 - 01:30 PM said:

You can easily write a funciton that does this for you.

there is no way to receive without specifying a URL with the given functions

http.listen does not specify which URL it is listening to

Orwell, on 15 January 2013 - 01:41 PM said:

Actually, TheOriginalBit posted one in this thread. :P/>

again, that requires a URL to be specified

Eh, you can't listen for inbound connections you know. That would be bad… And you'd need to have some knowledge to make servers accept those inbound connections (especially when behind NAT). And just.. it's wrong…

how is it wrong? the only way it could be bad would be if someone executed text received from a website that magically was malicious lua bytecode that wasn't stopped by dan200's sandbox

implementing a web server in lua running on a minecraft server is so self-evidently wrong I wouldn't even know where to begin explaining why it is wrong. Certainly not going to happen, though.

This doesn't even require one of the mod developers to No it.

No.