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howto shorten rs.bundledoutput(string, #) ?

Started by Andale, 31 January 2013 - 05:55 AM

Andale #1

46 posts

Location NWIndiana

Posted 31 January 2013 - 06:55 AM

I thought this would work, but I've not been able to figure this out.


local rbo = function(text)
rs.setBundledOutput(text, x)
end

It seems really simple but I'm not sure why it won't take the second variable from rbo=("left", 4)
Returns 'Expected string, number'

I'm sure its super simple but I've not found anyone else's program that didn't just have it typed out. I've gotta shorten it at least to reduce time/size. I've got 5 bundled outputs going.

Engineer #2

Engineer's profile picture

1522 posts

Location The Netherlands

Posted 31 January 2013 - 06:59 AM

try


rs.setBundledOutput(text, tonumber(x))

PixelToast #3

2217 posts

Location 3232235883

Posted 31 January 2013 - 07:12 AM

better:


rbo=rs.setBundledOutput

Andale #4

46 posts

Location NWIndiana

Posted 31 January 2013 - 07:39 AM

PixelToast, on 31 January 2013 - 07:12 AM said:
better:
rbo=rs.setBundledOutput

Oh my god. I had no idea you could just use variables in place of commands. Well, I'll be buggered. Thanks much.