[Lua][Question] Multiple inputs in code? (IDK correct terminology)

local args = {...}
for i = 1,tonumber(tArgs[1]) do
print("star")
end

local times = read()
local valid = tonumber(times)
if type(valid) ~= "number" then
 print("This is not a number")
 return
else
 for i = 1,valid do
  print("star")
 end
end

SuicidalSTDz, on 08 April 2013 - 03:27 PM said:

local args = {...}
for i = 1,tonumber(tArgs[1]) do
print("star")
end

Or inside a script:

local times = read()
local valid = tonumber(times)
if type(valid) ~= "number" then
print("This is not a number")
return
else
for i = 1,valid do
  print("star")
end
end

number = tonumber(string.sub(variable, 6, 6)) or 1 -- or 1 sets number to 1 if the other condition is nil 

variable = read()
space1 = string.find(variable, "%s")  -- searches the string for  space and returns the first occurence
counter = string.sub(variable,space1+1,#variable) -- we cut the string starting at the point where he found the space and suggest that everything after the space is the number for the loop
variable = string.sub(variable, 1, space1-1) -- now we cut the number of the inital string

number = tonumber(counter) or  false -- here we convert the entered counter to a number and set false if its not a number or not existing if so set value to false

if not number then -- if number false Print error
print "the second parameter must be a number" -- print error
else
for i = 1, number do
print(variable)  -- i print the text you entered before the number you can edit this if you want to print sth different
end
end

SuicidalSTDz, on 08 April 2013 - 03:27 PM said:

local args = {...}
for i = 1,tonumber(tArgs[1]) do
print("star")
end

-snip-

local tArgs = {...}
tArgs[1] = tArgs[1] or 1 -- if no 2nd argument is given, tArgs[1] is 1.
for i = 1,tonumber(tArgs[1]) do
print("star")
end

LordIkol, on 09 April 2013 - 04:55 AM said:

I'm on the mobile at the moment will paste code later if needed.
For your question about if substring etc..
Yes this would work.
To capture the error you can do the same thing I did for number to the space1 variable
Simply add or false
Then check if false and throw error message

variable = read()
space1 = string.find(variable, "%s")  -- searches the string for  space and returns the first occurence
if not space1 then
counter = 1
else
counter = string.sub(variable,space1+1,#variable) -- we cut the string starting at the point where he found the space and suggest that everything after the space is the number for the loop
variable = string.sub(variable, 1, space1-1) -- now we cut the number of the inital string
end


number = tonumber(counter) or  false -- here we convert the entered counter to a number and set false if its not a number or not existing if so set value to false

term.clear()
if not number then -- if number false Print error
print "the second parameter must be a number" -- print error
else
if variable == "star" then
for i = 1, number do
print(variable)  -- i print the text you entered before the number you can edit this if you want to print sth different
end
else 
print "wrong word"
end
end

LordIkol, on 09 April 2013 - 09:38 PM said:

Here is the fixed code

variable = read()
space1 = string.find(variable, "%s")  -- searches the string for  space and returns the first occurence
if not space1 then
counter = 1
else
counter = string.sub(variable,space1+1,#variable) -- we cut the string starting at the point where he found the space and suggest that everything after the space is the number for the loop
variable = string.sub(variable, 1, space1-1) -- now we cut the number of the inital string
end


number = tonumber(counter) or  false -- here we convert the entered counter to a number and set false if its not a number or not existing if so set value to false

term.clear()
if not number then -- if number false Print error
print "the second parameter must be a number" -- print error
else
if variable == "star" then
for i = 1, number do
print(variable)  -- i print the text you entered before the number you can edit this if you want to print sth different
end
else
print "wrong word"
end
end

else
  if blah == "blah" then
	for i =1, number do
	  -- whatever was in the rest of this if and for.
	end
   else
	-- Code
end

elseif

else
if

variable = read()
space1 = string.find(variable, "%s")  -- searches the string for  space and returns the first occurence
if not space1 then
  counter = 1
else
  counter = string.sub(variable,space1+1,#variable) -- we cut the string starting at the point where he found the space and suggest that everything after the space is the number for the loop
  variable = string.sub(variable, 1, space1-1) -- now we cut the number of the inital string
end


number = tonumber(counter) or  false -- here we convert the entered counter to a number and set false if its not a number or not existing if so set value to false

term.clear()
if not number then -- if number false Print error
  print "the second parameter must be a number" -- print error
elseif variable == "star" then
  for i = 1, number do
   print(variable)  -- i print the text you entered before the number you can edit this if you want to print sth different
  end
else
  print "wrong word"
end
end

Spongy141, on 10 April 2013 - 04:17 PM said:

LordIkol, on 09 April 2013 - 09:38 PM said:

Here is the fixed code

variable = read()
space1 = string.find(variable, "%s")  -- searches the string for  space and returns the first occurence
if not space1 then
counter = 1
else
counter = string.sub(variable,space1+1,#variable) -- we cut the string starting at the point where he found the space and suggest that everything after the space is the number for the loop
variable = string.sub(variable, 1, space1-1) -- now we cut the number of the inital string
end


number = tonumber(counter) or  false -- here we convert the entered counter to a number and set false if its not a number or not existing if so set value to false

term.clear()
if not number then -- if number false Print error
print "the second parameter must be a number" -- print error
else
if variable == "star" then
for i = 1, number do
print(variable)  -- i print the text you entered before the number you can edit this if you want to print sth different
end
else
print "wrong word"
end
end

I fixed this code as well :P/>/> there was still errors. But still, 1 please and I really can not stress this more to people, SPACE YOUR CODE!!! Alright now that I got that out of the way, when you put

else
  if blah == "blah" then
	for i =1, number do
	  -- whatever was in the rest of this if and for.
	end
   else
	-- Code
end

You cannot do that…. its should be

elseif

not

else
if

AND PLEASE SPACE!!!! Oh yeah and open this spoiler for the spaced code

Spoiler

variable = read()
space1 = string.find(variable, "%s")  -- searches the string for  space and returns the first occurence
if not space1 then
  counter = 1
else
  counter = string.sub(variable,space1+1,#variable) -- we cut the string starting at the point where he found the space and suggest that everything after the space is the number for the loop
  variable = string.sub(variable, 1, space1-1) -- now we cut the number of the inital string
end


number = tonumber(counter) or  false -- here we convert the entered counter to a number and set false if its not a number or not existing if so set value to false

term.clear()
if not number then -- if number false Print error
  print "the second parameter must be a number" -- print error
elseif variable == "star" then
  for i = 1, number do
   print(variable)  -- i print the text you entered before the number you can edit this if you want to print sth different
  end
else
  print "wrong word"
end
end

else
if

else
if

elseif

local tArgs = { ... }
    if #tArgs ~= 2 then
    print( "Usage: text count" )
    return
end

local text = tostring( tArgs[1] )
local count = tonumber( tArgs[2] )

for i = 1, count do
    print(text)
end

Spongy141, on 10 April 2013 - 07:46 PM said:

Actually since I remember recalling from a error I keept getting while trying to do

else
if

It didn't work and would give a error, so thats why you have to do (Or at least for me my programs never work unless I do a else if like this "elseif")

elseif

if something then
 --something
else
 if not foo then
  --something
 end
end