Simple password lock - Need Coding help

Im trying to get this code to open a door only when i enter password Runewar, otherwise if i enter the wrong password, to not open the door and shut down, but when i try to run it, i get this error: bios:206: [string "lock"]:4: '<eof>' expected, not entirely sure how to fix this

shell.run("clear")
print ("Enter the Password")
Password = ("Runewar")
end
if read("*") == Password then
shell.run("clear")
print ("Accepted")
redstone.setOutput("back",true)
end
else
shell.run("clear")
print("Go Away")
sleep(5)
shutdown

You have an extra end, i'll comment it below..

You also have a couple other errors I'll fix and comment

Password = ("Runewar") -- moved to top so you can check against later
shell.run("clear")
print ("Enter the Password")
pass = read("*") -- capture read as a var
--end  -- you dont need this
if pass == Password then -- check the output of the read vs the var Password
shell.run("clear")
print ("Accepted")
redstone.setOutput("back",true)
--end -- dont need this
else
shell.run("clear")
print("Go Away")
sleep(5)
os.shutdown() -- add ()'s and os.
end -- add this

Okay, with your new adjustments, it works fine, thx for the help a 3rd time xD

Here's a cleaned up copy without the comments, it should work. Runs fine on mine.

Password = ("Runewar") -- moved to top so you can check against later
shell.run("clear")
print ("Enter the Password")
pass = read("*")
if pass == Password then
shell.run("clear")
print ("Accepted")
redstone.setOutput("back",true)
else
shell.run("clear")
print("Go Away")
sleep(5)
os.shutdown()
end

Better use

local Password = "Runewar"

instead of

Password = "Runewar"

else it the variable Password counts for ANY Program you run that session