already another problem

c = a m b

local n1 = 5
local n2 = 10
local calculation =  n1 + n2
-- If you print calculation 15 will come out of it

Freack100, on 18 May 2013 - 09:21 AM said:

I think you can't save math operators in variables :)/>/>

local a = 2
--# we cannot save mathematical operators into a variable, we must save them as a string
local m = '+'
local b = 5

--# we need 3 things, the two numbers, and the mathematical operator in string form
local function calculate1(num1, num2, op)
  --# now we check which operator it is and return the result based off that operator
  if op == '+' then
	return num1 + num2
  elseif op == '-' then
	return num1 - num2
  elseif op == '/' then
	return num1 / num2
  elseif op == '*' then
	return num1 * num2
  end
  --# no valid operator supplied
  error('Invalid operator: '..tostring(op), 0)
end

--# we need 3 things, the two numbers, and the mathematical operator in string form
local function calculate2(num1, num2, op)
  --# we use loadstring to put our values into a statement
  local func = loadstring( 'return '..num1..' '..op..' '..num2 )
  --# run the loadstring function
  return func()
  --# note we can do the above 2 lines in one line, I split it out to make it more apparent whats happening, this is how you would do it in one line
  --# return loadstring( 'return '..num1..' '..op..' '..num2 )()
end

print(calculate1(a, b, m))
print(calculate2(a, b, m))

theoriginalbit, on 18 May 2013 - 09:55 AM said:

ok so this is 2 of the ways to get what you want done.

just our numbers to test with

local a = 2
--# we cannot save mathematical operators into a variable, we must save them as a string
local m = '+'
local b = 5

method 1

--# we need 3 things, the two numbers, and the mathematical operator in string form
local function calculate1(num1, num2, op)
  --# now we check which operator it is and return the result based off that operator
  if op == '+' then
	return num1 + num2
  elseif op == '-' then
	return num1 - num2
  elseif op == '/' then
	return num1 / num2
  elseif op == '*' then
	return num1 * num2
  end
  --# no valid operator supplied
  error('Invalid operator: '..tostring(op), 0)
end

method 2

--# we need 3 things, the two numbers, and the mathematical operator in string form
local function calculate2(num1, num2, op)
  --# we use loadstring to put our values into a statement
  local func = loadstring( 'return '..num1..' '..op..' '..num2 )
  --# run the loadstring function
  return func()
  --# note we can do the above 2 lines in one line, I split it out to make it more apparent whats happening, this is how you would do it in one line
  --# return loadstring( 'return '..num1..' '..op..' '..num2 )()
end

test the functions

print(calculate1(a, b, m))
print(calculate2(a, b, m))

tonkku107, on 23 May 2013 - 11:46 AM said:

Thanks! is there any way of putting like 10-2 into a single input (10 would ne num1 - will be op and 2 will be num2)?

theoriginalbit, on 23 May 2013 - 12:10 PM said:

tonkku107, on 23 May 2013 - 11:46 AM said:

Thanks! is there any way of putting like 10-2 into a single input (10 would ne num1 - will be op and 2 will be num2)?

Not quite sure what you mean. do you mean like the loadstring method where its all put into one string?

tonkku107, on 23 May 2013 - 12:15 PM said:

I mean if i input like 3+4 it can count it

theoriginalbit, on 23 May 2013 - 12:21 PM said:

tonkku107, on 23 May 2013 - 12:15 PM said:

I mean if i input like 3+4 it can count it

Count or calculate?

theoriginalbit, on 23 May 2013 - 12:21 PM said:

i.e. would the input say 3 (number of parts) or 7 (the sum of 3 and 4)
If you mean calculate then BOTH of the methods that I provided will calculate the result of 3+4 and return the value.

tonkku107, on 23 May 2013 - 12:54 PM said:

if i input 3+4 it will say: 7
Like So:
>program
What would you like to caculate ( or count i don't know): 3+4
It is 7!
>_