call function from string

function foofunc ()
  print ("foo")
end

x='foofunc'

_G[x]()

function foofunc ()
  print ("foo")
end

x = loadstring("foofunc()")
x()

-- Or just:

loadstring("foofunc()")()

Bomb Bloke, on 26 May 2013 - 08:46 AM said:

function foofunc ()
  print ("foo")
end

x = loadstring("foofunc()")
x()

-- Or just:

loadstring("foofunc()")()

function _G['foobar']()
  print("foo")
end

_G["foobar"]()

local functions = {}
function functions['foobar']()
   print("foobar")
end

local x = 'foobar'
functions[x]()

Engineer, on 26 May 2013 - 08:57 AM said:

local functions = {}
function functions['foobar']()
  print("foobar")
end

local x = 'foobar'
functions[x]()

Calimore, on 26 May 2013 - 12:52 PM said:

Unfortunately this does not work… Error is: '(' expected in line 2

functions['foobar'] = function()
  print("foobar")
end

function functions.foobar()
  print("foobar")
end

theoriginalbit, on 26 May 2013 - 12:55 PM said:

Calimore, on 26 May 2013 - 12:52 PM said:

Unfortunately this does not work… Error is: '(' expected in line 2

Yeh you need to do one of these two

functions['foobar'] = function()
  print("foobar")
end

or this

function functions.foobar()
  print("foobar")
end

Calimore, on 26 May 2013 - 01:01 PM said:

Ahh… much better! This is it…

Thanks a lot :lol:/>

functions["some name"] = function()
  print("foo")
end

function functions.other name()
  print("bar")
end

theoriginalbit, on 26 May 2013 - 01:05 PM said:

Oh I should mention if you want a key with a space in it, you will need to use the first method.

Calimore, on 26 May 2013 - 03:28 PM said:

I suspect the same goes for numbers. I was having problems with that… ;)/>

local t = {}
local t[1] = function()
   print("I'm index 1!")
end

function myfunc()
  print("Hello World")
end

fname = "myfunc"

getfenv()[fname]()