splitting a string and store the parts in different variables.

local string = "variable1 variable2"

for i in string.gmatch(string, "%S+") do
 -- what to do now to store variable1 and variable2 in DIFFERENT variables again.?
end

local splittedStrings = {}
for s in stringName:gmatch("[%S]+") do
   table.insert( splittedStrings, s )
end

tabelA = {"train1","U1","etc..."}
tabelB = {
			   ["train1"] = {"linie","ziel","etc..."},
			   ["trainETC..."] = {"linie","ziel","etc..."}
			   }

tabelB[tabelA[1]][1] = tabelA[2]

local trainsBuffer = { }
trainInfo = nil
trains = {
	    ["train1"] = {"linie","ziel","station","direction"},
        ["train2"] = {"linie","ziel","station","direction"},
        ["train3"] = {"linie","ziel","station","direction"},
        ["train4"] = {"linie","ziel","station","direction"}
        }
function interpret()
 trains[trainsBuffer[1]][1] = trainsBuffer[2]
 trains[trainsBuffer[1]][2] = trainsBuffer[3]
 trains[trainsBuffer[1]][3] = trainsBuffer[4]
 trains[trainsBuffer[1]][4] = trainsBuffer[5]
end
function rednetGetInput()
 while true do
  senderId, trainInfo, distance = rednet.receive()
  print(trainInfo) print("<-- traininfo")
  for s in trainInfo:gmatch("[%S]+") do
    table.insert(trainsBuffer , s )
    print("s ist: "..s)
  end
  interpret()
  --monitor()
 end
end
rednetGetInput()

local tabelA = { "string"; "something"; "x" }
local tabelB = { "gnirts"; "gnihtemos"; "x" }

for k, v in pairs( tabelA ) do
  tabelB[ v ] = tabelB[ k ]
end

local tableB = { 
  [1] = "gnirts"; 
  [2] = "gnihtemos"; 
  [3] = "x";
  ["string"] = "gnirts";
  ["something"] = "something";
  ["x"] = "x"
}

--this is tabelA. all the times are stored in it. the times are NOT ordered.
tabelA = {
			  ["train1"] = {"20"},
			  ["train2"] = {"60"},
			  ["train3"] = {"40"},
			  ["train4"] = {"80"}
			  }
--this is tabelB, at the end it should contain the times of all four trains. The key is for defining and the value should be the corresponding train.
tabelB = {
			 [1] = " "
			 [2] = " "
			 [3] = " "
			 [4] = " "
			 }
-- so as an example of an correctly filled tabel:
[1] = "train1"
[2] = "train3"
[3] = "train2"
[4] = "train4"

mlewelt, on 11 July 2013 - 02:24 PM said:

Hello once again.
My program is almost finished. but there is one thing i just cant figure out. i searched a long time, but all solutions i got werent the right ones.
So, here´s my problem:
I want to sort values in a table:

--this is tabelA. all the times are stored in it. the times are NOT ordered.
tabelA = {
			  ["train1"] = {"20"},
			  ["train2"] = {"60"},
			  ["train3"] = {"40"},
			  ["train4"] = {"80"}
			  }
--this is tabelB, at the end it should contain the times of all four trains. The key is for defining and the value should be the corresponding train.
tabelB = {
			 [1] = " "
			 [2] = " "
			 [3] = " "
			 [4] = " "
			 }
-- so as an example of an correctly filled tabel:
[1] = "train1"
[2] = "train3"
[3] = "train2"
[4] = "train4"

cant figure out how to sort these.
any help is appreciated ;)/>

local tableA = {
				[0] = {"train0", "20"},
				[1] = {"train1", "60"},
				[2] = {"train2", "40"},
				[3] = {"train3", "80"},
				[4] = {"train4", "20"},

				}

t = tableA
	
table.sort(t, function(a, B)/>   -- why does it add a /> here every time i edit...
	return tonumber(a[2]) > tonumber(b[2])
end)

for i = 1,#t do
  print(t[i][1])
end

table = {
	[1] = {"something", "high"}
	[2] = {"something else", "low"}
	[3] = {"something further", "medium"},
	[4] = {"yet more something", "medium"},
}
priorities = {high = 2, medium = 1, low = 0}
table.sort(t, function(e1, e2)
	return priorities[e1[2]] > priorities[e2[2]]
end)

function newdata(nr, ti) -- insert data
  local u = {}
  u[1] = nr
  u[2] = ti
  return u
end