[Api] Need Help With Prefix & Suffix

If i work with basic APIs like this one

superU:

function hello()
print("Hello World");
end

and i want to use it in another file i do this

os.loadAPI("superU")
superU.hello();

how do i use it when the name of the api isn't superU but "superU.properties"?

Thanks for your help.

I would say your wanting to access it when its saved as something else I would probably store it to a directory called api ( put all api's in there) and then do a code like

  apis = fs.list("/api") for I = 1, #apis do os.loadApi(apis[I]) end 

I don't have time to look at the os.loadAPI function right now but I think this is the only way to do it.

Expose your properties object or "sub-api" as a part of the superU api

file: superU

properties = {
  fun="yes",
  goodbye = function ()
	print("Goodbye")
  end
}

function hello()
  print("Hello World")
end

This would enable you to access the properties table just like you accessed the hello function. They're both contained in the superU api.

os.loadAPI("superU")
superU.hello()

print("This is "..superU.properties.fun.."!")

superU.properties.goodbye()

I don't think you'd be able to simply save your api file as "superU.properties" and load it as an api. The period [.] is a special character when it comes to referencing variables.

If the filename is SuperU.properties, you would need to use _G["SuperU.properties"].whatever() to access the whatever() function it contained.

Don't use periods in API names.

Thanks for your help:

Lyqyd, on 01 August 2013 - 03:52 PM said:

If the filename is SuperU.properties, you would need to use _G["SuperU.properties"].whatever() to access the whatever() function it contained.

Don't use periods in API names.

You could rename it, quite easily:

_G.superU = _G["superU.properties"]
_G["superU.properties"] = nil

I hope it's clear how this works.