Turtle Ignore the last move in the loop

local tArgs = {...}

term.clear()
term.setCursorPos(1,1)
print("Digging:")
print("  "..tArgs[1].." blocks Down")
print("  "..tArgs[2].." blocks Forward")
print("  "..tArgs[3].." blocks Side")
term.setCursorPos(18, 9)
textutils.slowPrint("made by okok99haha")

function down()
for i = 1, tArgs[1] do
  while not turtle.down()
	do turtle.digDown()
end
end
end

function up()
for i = 1, tArgs[1] do
  while not turtle.up()
	do turtle.digUp()
end
end
end

function forward()
  while not turtle.forward()
	do turtle.dig()
end
end

function line()
  for aa = 1, tArgs[2] do
	down()
	up()
	forward()
end
end

function turn()
turtle.turnRight()
turtle.turnRight()
end

function back()
for ab = 1, tArgs[2] do
turtle.forward()
end
end

function moveLine()
turtle.turnLeft()
turtle.forward()
turtle.turnLeft()
end

for i = 1, tArgs[3] do
  line()
  turn()
  back()
  moveLine()
end

term.setCursorPos(1,11)
print("Done!")
print("Print Any Key to Exit")
os.pullEvent("key")
term.clear()
term.setCursorPos(1,1)

Lyqyd, on 08 August 2013 - 08:24 PM said:

Split into new topic.

You could check if the current iteration is less than the maximum and only call the function if it is. A simple if statement around the function call in question will solve this nicely.

function line()
  for aa = 2, tArgs[2] do
    down()
    up()
    forward()
  end
  down()
  up()
end

reububble, on 10 August 2013 - 12:28 AM said:

function line()
  for aa = 2, tArgs[2] do
	down()
	up()
	forward()
  end
  down()
  up()
end

Should do the trick but only if args[2] is never less than 2. Your problem could be because when you use arguments they are entered in string form, so you might need to either change args[2] to a number by using
args[2] = tonumber(args[2])
or by using tonumber(args[2]) in the line you check it.

while true do
  -- Lots of turtley things
  -- including digging
  -- and moving
  -- then running out of fuel
  if turtle.getFuelLevel() < 10 then
    turtle.select(whatever slot the coal should be in)
    turtle.refuel(1)
  end
end

reububble, on 10 August 2013 - 06:23 AM said:

There exists a function called turtle.getFuelLevel Obviously, it returns the turtle's fuel level… You could create a part of your turtle's routine to check this function. A suitable snippet of code could be

 while true do -- Lots of turtley things -- including digging -- and moving -- then running out of fuel if turtle.getFuelLevel() < 10 then turtle.select(whatever slot the coal should be in) turtle.refuel(1) end end 

Do be careful though, I used an if statement here, which means that it won't repeat the refueling process if it didn't work the first time. That means that if there is no fuel in the slot, the turtle will continue to roll around in a paraplegic heap on the ground. No offense to any paraplegic persons, it's a serious condition. That should be the most of it you need to know.

while turtle.getFuelLevel() < 10 do

reububble, on 11 August 2013 - 07:54 AM said:

Yes just change the if statement to a while statement.

while turtle.getFuelLevel() < 10 do