piston airlock

I am trying to make a piston airlock and I was wondering how to make it so at a certant point it will go back to a place in the command, Here is my script:

redstone.setOutput("right", true)
print "Type 'open' or 'close' to Open or close the airlock."
function A()
print ""
write ">"
input = read()
if input == "open" then
   print "Opening..."
   redstone.setOutput("right", false)
   A()
else
   print "Command not recognised."
   A()
end
if input == "close" then
   print "Closing..."
   redstone.setOutput("right", true)
   A()
else
   print "Command not recognised."
   A()
end
end

When I try to run it it just says the first line and then goes to the normal console. Help?

@qwerty you never call A() and also its bad to call A() within A() it will lead to a stack error use a while loop

jay5476, on 28 August 2013 - 05:44 PM said:

@qwerty you never call A() and also its bad to call A() within A() it will lead to a stack error use a while loop

Do you think you could suggest to me how to make it better so it works?

what on earth did you post this question in this old, unrelated thread for?

qwerty6543, on 28 August 2013 - 05:36 PM said:

I am trying to make a piston airlock and I was wondering how to make it so at a certant point it will go back to a place in the command, Here is my script:

redstone.setOutput("right", true)
print "Type 'open' or 'close' to Open or close the airlock."
function A()
print ""
write ">"
input = read()
if input == "open" then
   print "Opening..."
   redstone.setOutput("right", false)
   A()
else
   print "Command not recognised."
   A()
end
if input == "close" then
   print "Closing..."
   redstone.setOutput("right", true)
   A()
else
   print "Command not recognised."
   A()
end
end

When I try to run it it just says the first line and then goes to the normal console. Help?

You really should have posted a new topic instead of replying to an old one like this.

But to answer your question you dont even need to have a function. Just put certain parts of the code in a loop. You also do not need two if statements, you can do what your wanting using an elseif in the statement.

redstone.setOutput("right", true)
print "Type 'open' or 'close' to Open or close the airlock."

while true do
print ""
write ">"
input = read()
if input == "open" then
   print "Opening..."
   redstone.setOutput("right", false)
elseif input == "close" then
   print "Closing..."
   redstone.setOutput("right", true)
else
   print "Command not recognized."
end
end