Return If File Exists In Any Directory

I know about fs.exists(string path) But if I'm in the main directory, and I want to see if you can run "dance" for example, it will return false. Is there a way to see if that file exists on the computer?

this is just from my head

function check(dir, file)
f = fs.list(dir)
for k, v in pairs(f) do
    local path = fs.combine(dir, v)
    if not fs.isReadOnly(path) then
      if fs.isDir(path)
      check(path) -- check the directory
    else
       if path == file then
      return true
      end
    end
  end
end

that should work

jay5476, on 31 August 2013 - 05:03 AM said:

this is just from my head

function check(dir, file)
f = fs.list(dir)
for k, v in pairs(f) do
	local path = fs.combine(dir, v)
	if not fs.isReadOnly(path) then
	  if fs.isDir(path)
	  check(path) -- check the directory
	else
	   if path == file then
	  return true
	  end
	end
  end
end

that should work

Missing one then I'm sure you mean "if fs.isDir(path) then" I'll post more when I have more info on if it worked or not. I'm kinda swamped with stuff to do at the moment.

jay5476, on 31 August 2013 - 05:03 AM said:

this is just from my head

function check(dir, file)
f = fs.list(dir)
for k, v in pairs(f) do
	local path = fs.combine(dir, v)
	if not fs.isReadOnly(path) then
	  if fs.isDir(path)
	  check(path) -- check the directory
	else
	   if path == file then
	  return true
	  end
	end
  end
end

You'll also need to pass 'file' to the every recursive call of 'check'.

It sounds kind of like shell.resolveProgram is what you're looking for, unless you really need to find it in any directory, rather than just determining if the string input resolves to a file on the path or in the current directory.