"If" statement math

i'm a slopy programer, if it works i do it i dont care if there is a better way.

i'm writeing a simple code to take nugets (from Tinkers Construcs ore berry bushes) and useing a advanced crafty turtle. even out the nugets in slots 6,7,8,10,11,12,14,15,16. then craft them into ingots.

Is there a way i could only pull out of the chest a amount divisible of 9? or some other way to do it.

(sorry about the spelling)

Here Is What I Have So Far
———————————-

local g = 6

function Sort()
turtle.select(6)
turtle.suckUp(9)
for i=6,8 do
turtle.transferTo(i,1)
end
for u=10,12 do
turtle.transferTo(u,1)
end
for y=14,16 do
turtle.transferTo(y,1)
end
end

function Drop()
for i=1,16 do
turtle.select(i)
turtle.drop()
end
end

(this is the part i need help with)

if turtle.getItemCount(g) == 9 then
Sort()
elseif turtle.getItemCount(g) == 18 then
Sort()
Sort()
elseif turtle.getItemCount(g) == 27 then
Sort()
Sort()
Sort()
end

(thats what i started and i could work but i'm sure that there is a better way(and i dont want to type the same thing over and over))


Drop()
turtle.select(1)


If you can help thanks!

cool thanks, i didnt know that you could do something like this
turtle.dropUp(turtle.getItemCount(1) % 9)

Also, in case you didn't know, the " % " means modulus, same thing as remainder. So "4 % 3" is 1 because 4/3 = 1 remainder 1, "5 % 3" is 2 and so on.
Just thought I'd point that out.