Loading API help

Hey guys. I was wondering how to correctly load API's with a file extension. I have tried

os.loadAPI("API.lua");
API.lua.function();

which does not work, and neither does

os.loadAPI("API.lua");
API.function();

Do I need to rename the file, or can I use that way?
Thanks in advance

You might be able to do this:

_G["API.lua"].function()

… but quite frankly, I can only recommend removing the extension.

Bomb Bloke is indeed correct. you would be able to access it directly through the global table and the simplest solution would be to remove the extension from the file.

however if you don't want to remove the extension or you can't remove the extension (i.e. if your text editor requires it), I did write an alternative to os.loadAPI a while back that would remove any extension if present.

local function loadAPI(path)
  --# check the file exists
  if not fs.exists(path) then
	error("File does not exist", 2)
  end
  --# check the path isn't a directory
  if fs.isDir(path) then
	error("Cannot load directory", 2)
  end
  --# get the filename and extension (if exists)
  local name = fs.getName(path)
  --# remove the extension (if exists)
  name = name:match("(%a+)%.?.-")
  --# check there isn't an API loaded under this name
  if _G[name] then
	error("API "..name.." already loaded", 2)
  end
  --# os.loadAPI logic
  local env = setmetatable({}, { __index = _G })
  local func, err = loadfile(path)
  if not func then
	error(err, 0)
  end
  setfenv(func, env)
  func()
  local api = {}
  for k,v in pairs(env) do
	api[k] =  v
  end
  _G[name] = api
  return true
end

It strikes me that you could also do this:

os.loadAPI("API.lua")
local API = _G["API.lua"]

API.function()

Still a bit messy, but certainly simple.