Need help on server-side computer

When I try to execute this code it presents me with ''rednet:87: Number Expected''. Can someone please help?

term.clear()
rednet.open("front")
function refreshScreen()
  term.scroll(3)
  term.setCursorPos(1,1)
  term.setTextColor(1)
  print("Obscure Frameworks		   ")
  print("Mainframe V_0.1			  ")
  computerID = os.getComputerID()
  computerVersion = os.version()
  computerLabel = os.getComputerLabel()
  print("System Details:			  ")
  print("System Version: "..computerVersion)
  print("		 Label: "..computerLabel)
  print("		    ID: "..computerID)
  print("+--------System Log---------+")
  end
 
  refreshScreen()
 
while true do
  event, senderId, message, protocol = os.pullEvent("rednet_message")
  term.setCursorPos(1,23)
 
  if senderId == null then
    term.setTextColor(16384)
    print("Network Error!")
    print("  SID is null!")
    print("  Packet Blocked.")
    elseif message == null then
    term.setTextColor(16384)
    print("Network Error!")
    print("  Message is null!")
    print("  Packet Blocked.")
    elseif protocol == null then
    term.setTextColor(16384)
    print("Network Error!")
    print("  Protocol is null!")
    print("  Packet Blocked.")
    else
    term.setTextColor(8)
    print("Network Event!")
    print("  SID: "..senderId)
    print("  Message: "..message)
    print("  Protocol: "..protocol)
    if protocol ~= 4 then
   rednet.send(protocol,message,senderId)
   end
    end
  refreshScreen()
end

Where you use rednet.send you do protocol, message, senderId you need to do senderId, message, protocol in that order. Id first message second protocol last.

valithor, on 21 November 2014 - 11:42 PM said:

Where you use rednet.send you do protocol, message, senderId you need to do senderId, message, protocol in that order. Id first message second protocol last.

All right, that works. Thanks!