list

t = {fs.list(path)}
for i = 1, #t do
  print(t[i])
end

doesn't return what i want

I believe fs.list returns a table. So basically you're seeing t[1] being a table.

t = fs.list(path)
for i = 1, #t do
  print(t[i])
end

Dragon53535, on 14 February 2015 - 04:59 AM said:

I believe fs.list returns a table. So basically you're seeing t[1] being a table.

 t = fs.list(path) for i = 1, #t do print(t[i]) end 

that's the same thing i wrote down…whats wrong with the code i wrote?

slow-coder, on 14 February 2015 - 01:43 PM said:

that's the same thing i wrote down…whats wrong with the code i wrote?

Your code:

t = {fs.list(path)}

Dragon's code:

t = fs.list(path)

It's not the same code you wrote. What you are doing in your code is putting all return values of fs.list into a table, which you then save to a variable. What Dragon53535 is doing is putting the first (and only) return value into a variable. fs.list return a numerically indexed table, so there is no need to put it into another table.

ohhhhh ok