12 posts
Posted 13 March 2015 - 11:27 PM
Heres the error bios:366: [string "guess"]:7: ambiguous syntax (function call x new statement)
heres the code
print("think of the number (1-100")
number = math.random(1,100)
while true do
number = io.read()
(if) number == tonumber(number) then
print("damn, youre a good guesser")
break
else
if tonumber(number) > number then
print("Too low")
else
print("Too High")
end
please help.
957 posts
Location
Web Development
Posted 14 March 2015 - 12:11 AM
First, put code in code blocks: [.code] [./code]
(With out the period)
Second, your error is a simple fix:
you put 'if' in parentheses (Which Lua thinks is some sort of function)
(On line 7)
Looking over your code, I think you'll run into an eof error after you fix this one
print("think of the number (1-100")
number = math.random(1,100)
while true do
number = io.read()
if number == tonumber(number) then
print("damn, youre a good guesser")
break
elseif tonumber(number) > number then --#make else and if into one word, elseif
print("Too low")
else
print("Too High")
end
end --#After indenting, we see that you need another 'end' for the while statement
Code errors aside, this won't work as you intend. You set 'number' to a random number, then override it with the user input!
Edited on 13 March 2015 - 11:14 PM
12 posts
Posted 14 March 2015 - 12:36 AM
First, put code in code blocks: [.code] [./code]
(With out the period)
Second, your error is a simple fix:
you put 'if' in parentheses (Which Lua thinks is some sort of function)
(On line 7)
Looking over your code, I think you'll run into an eof error after you fix this one
print("think of the number (1-100")
number = math.random(1,100)
while true do
number = io.read()
if number == tonumber(number) then
print("damn, youre a good guesser")
break
elseif tonumber(number) > number then --#make else and if into one word, elseif
print("Too low")
else
print("Too High")
end
end --#After indenting, we see that you need another 'end' for the while statement
Code errors aside, this won't work as you intend. You set 'number' to a random number, then override it with the user input!
https://www.youtube.com/watch?v=seuWeVZkETw skip to 23 minutes i had my setup exactly the same as his but it gave me this error bios 366 [string "guess"]:5: unexpected symbol
957 posts
Location
Web Development
Posted 14 March 2015 - 12:59 AM
https://www.youtube....h?v=seuWeVZkETw skip to 23 minutes i had my setup exactly the same as his but it gave me this error bios 366 [string "guess"]:5: unexpected symbol
If your code was the code you posted, then
you didn't have it exactJust realized his code is cut off, since the screen only shows so much.
You pretty much did have it exact, but you missed a few important 'end' s
Line 5 could have given you an unexpected symbol if you reversed 'io.read()' and 'guess'.
io.read() = guess --# This will error, since it is trying to set 'io.read()' to 'guess'
'guess = io.read()' by itself should be fine
12 posts
Posted 14 March 2015 - 04:56 AM
https://www.youtube....h?v=seuWeVZkETw skip to 23 minutes i had my setup exactly the same as his but it gave me this error bios 366 [string "guess"]:5: unexpected symbol
If your code was the code you posted, then
you didn't have it exactJust realized his code is cut off, since the screen only shows so much.
You pretty much did have it exact, but you missed a few important 'end' s
Line 5 could have given you an unexpected symbol if you reversed 'io.read()' and 'guess'.
io.read() = guess --# This will error, since it is trying to set 'io.read()' to 'guess'
'guess = io.read()' by itself should be fine
thanks i got it working
12 posts
Posted 14 March 2015 - 05:10 AM
https://www.youtube....h?v=seuWeVZkETw skip to 23 minutes i had my setup exactly the same as his but it gave me this error bios 366 [string "guess"]:5: unexpected symbol
If your code was the code you posted, then
you didn't have it exactJust realized his code is cut off, since the screen only shows so much.
You pretty much did have it exact, but you missed a few important 'end' s
Line 5 could have given you an unexpected symbol if you reversed 'io.read()' and 'guess'.
io.read() = guess --# This will error, since it is trying to set 'io.read()' to 'guess'
'guess = io.read()' by itself should be fine
its actually not working
there arent any errors its just that there is no right number
any tips?
8543 posts
Posted 14 March 2015 - 05:26 AM
Please paste the current code.
957 posts
Location
Web Development
Posted 14 March 2015 - 05:30 AM
its actually not working
there arent any errors its just that there is no right number
any tips?
Make sure you use separate variables for the user input and the random number
If you are still stumped, like Lyqyd said, paste the current code.
12 posts
Posted 14 March 2015 - 05:40 AM
its actually not working
there arent any errors its just that there is no right number
any tips?
Make sure you use separate variables for the user input and the random number
If you are still stumped, like Lyqyd said, paste the current code.
i feel dumb but im still stumped
print("Guess that number (1-100)")
number = math.random(1,100)
while true do
guess = io.read()
if guess == tonumber(guess) then
print("damn youre a good guesser")
break
elseif tonumber(guess) > number then
print("Too High")
else
print("Too Low")
end
end
7083 posts
Location
Tasmania (AU)
Posted 14 March 2015 - 05:58 AM
guess == tonumber(guess)?
12 posts
Posted 14 March 2015 - 06:04 AM
guess == tonumber(guess)?
ive never written so im not sure what needs to be changed
7083 posts
Location
Tasmania (AU)
Posted 14 March 2015 - 06:13 AM
I'd suggest comparing number to a numeric version of guess instead.
12 posts
Posted 14 March 2015 - 06:21 AM
I'd suggest comparing number to a numeric version of guess instead.
i dont know what that means lol
im not a programmer i just started computercraft (learning le basics)
7083 posts
Location
Tasmania (AU)
Posted 14 March 2015 - 06:24 AM
Your seventh line reads like this:
if guess == tonumber(guess) then
You are comparing the string "guess" to a numeric representation of "guess". They will never be equal, because on one side you've got a string, and on the other you've got a number.
You
want to compare your guess to your hidden number:
if number == tonumber(guess) then
12 posts
Posted 14 March 2015 - 06:31 AM
Your seventh line reads like this:
if guess == tonumber(guess) then
You are comparing the string "guess" to a numeric representation of "guess". They will never be equal, because on one side you've got a string, and on the other you've got a number.
You
want to compare your guess to your hidden number:
if number == tonumber(guess) then
thanks all you guys rock!!