attempt to call nill using rs. commands

so here is the function that errors

function powerup2()
print("powering all redstone lines")
rs.setBundledOutput("left", colors.cyan)
rs.setBundledOuput("left", (colors.combine(rs.getBundledInput("left"), colors.red))) <—- code errors here with attempt to call nill
rs.setBundledOuput("left", (colors.combine(rs.getBundledInput("left"), colors.green)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledInput("left"), colors.yellow)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledInput("left"), colors.orange)))
print("all redstone lines engaged")
listen()
end

any ideas? am i approaching the redpower commands wrong? the idea is to get computers talking on the bundled cable , is this possible on one bundle?

thanks in advance
blunty (bnbserver.co.uk)

"Ouput"
You need to write "Output"
attempt to call nil = syntax error

like so ?

function powerup2()
print("powering all redstone lines")
rs.setBundledOutput("left", colors.cyan)
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.red))) <—- attempt to call nil error here still
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.green)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.yellow)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.orange)))
print("all redstone lines engaged")
listen()
end

have also tried various other ays of using the commands , such as spreading them out to multiple steps and using variables , all to no avail

so i set up a test rig and this is the new error

rs.setBundledOutput("left", colors.cyan)
d = colors.test (rs.getBundledInput("left"), colors.cyan)
print(d) <— returns "true"
rs.setBundledOutput("left", (color.combine(rs.getBundledInput("left"), colors.red))) <—- errors here with "attempt to index ? (a nil value)"
e = rs.testBundledOutput("left", colors.red)
print(e)

note have tried both BundledInput and BundledOutput and get the same result

edit : have now found the lua prompt , entering that line into it provides no errors on its own

rs.setBundledOutput("left", (color.combine(rs.getBundledInput("left"), colors.red))) – "colors.combine" and not "color.combine"

exclent the test rig now works , but i cant spot any errors in the original function , ill post the whole program now as it might be a wider issue

-- master control program
function healthcheck()
x = 0
y = 0
z = 0
rs.setBundledOutput("left", colors.black)
if rs.testBundledInput("left", colors.black) == true then
print("conection confirmed")
powerup2()
else
print("connection broken")
end
end
function powerup2()
print("powering all redstone lines")
rs.setBundledOutput("left", colors.cyan)
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.red)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.green)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.yellow)))
rs.setBundledOuput("left", (colors.combine(rs.getBundledOutput("left"), colors.orange)))
print("all redstone lines engaged")
listen()
end
function listen()
print("listening for change of redstone state on red wire")
red = rs.testBundledInput("left", colors.red)
while red == true do
red = rs.testBundledInput("left", colors.red)
print("retrying in 20 seconds")
sleep(20)
end
if red == false then
print("change of state found")
phase2()
end
end
function phase2()
print("phase 2 now active")
x = (x + 1)
d = rs.getBundledInput("left")
e = colors.combine(d, colors.red)
rs.setBundledOutput("left", e)
print("red line reactivated")
d = rs.getBundledInput("left")
e = colors.subtract(d, colors.green)
rs.setBundledOutput("left", e)
print("green line deactivated")
if x == 8 then
x = 0
phase3()
else
listen()
end
end
function phase3()
print("phase 3 now active")
y = (y + 1)
d = rs.getBundledInput("left")
e = colors.subtract(d, colors.yellow)
rs.setBundledOutput("left", e)
print("yellow line deactivated")
if y == 8 then
y = 0
phase4()
else
listen()
end
end
function phase4()
print("phase 4 now active")
z = (z + 1)  
d = rs.getBundledInput("left")
e = colors.subtract(d, colors.orange)
rs.setBundledOutput("left", e)
print("orange line deactivated")
print("this factory has made", z, "HV solar cells")
listen()
end
healthcheck()

So whats the error?

factoryv2:17:attempt to call nill

KevinW1998, on 13 July 2012 - 09:50 AM said:

"Ouput"
You need to write "Output"
attempt to call nil = syntax error

You've should read this post

*HEADDESK* now i feel silly