19 posts
Latvia
Posted 11 April 2016 - 07:34 PM
Please, how can i make that when lever are down time goes but if lever again puts up it exit the program and goes back onother command called "m"
print("Set game time") --only need minutes
print("Minutes?") --only need minutes
write("-> ")
minute = tonumber(read()) --input directly as number(avoid string)
print("Seconds") --only need minutes
write("-> ")
sec = tonumber(read()) --input directly as number(avoid string)
print("Time added, press button to start countdown")
print("STOP TIME- ctrl + t then m ")
mon.setCursorPos(8,3)
mon.write("1")
local j = sec --declare seconds variable
local i = minute ---declare minutes variable
min = i
sleep(1)
--Returning Results
mon.setTextScale(5)
mon.setCursorPos(7,5)
mon.write(min..":"..sec)
os.pullEvent("redstone")
if rs.getInput("left") then
rs.setOutput("right",false)
repeat
if i > 0 then
if j > 0 then
j = j - 1
else
j = 59
i = i - 1
end
else
if j > 0 then
j = j - 1
else
done = true
end
end
if j > 9 then
sec = j
else
sec = "0"..j
end
min = i
sleep(1)
if i < 10 then
mon.setCursorPos(11,5)
mon.write(".")
end
--Returning Results
mon.setTextScale(5)
mon.setCursorPos(6,5)
mon.write(min..":"..sec.." ")
until j == 0 and i == 0
rs.setOutput("top",true)
rs.setOutput("right",true)
sleep(2)
rs.setOutput("top",false)
-- trigger redstone output
sleep(1)
end
