Monitor resolution

Hello,
I have some problems trying to calculate the monitor resolution using some math…
Esample

Input: 3x2 monitor
Resolution = ?

I thought that it follows some simple math rules like "screenResolution_x = nMonitor_x*7-(nMonitor_x-1)*4" but it's not so straight forward. :(/>/>
So, there is any function or API that can help me?
Thank you :)/>/>

EDIT: Solved problem

I solved the problem using a big table that involve x and y values and also scales.
To help future users here is the full table:

screenResolution = {
["0.5"] = {{15,36,57,79,100,121,143,164},{10,24,38,52,67,81}},
["1"]   = {{7,18,29,39,50,61,71,82},{5,12,19,26,33,40}},
["1.5"] = {{5,12,19,26,33,40,48,55},{3,8,13,17,22,27}},
["2"]   = {{4,9,14,20,25,30,36,41},{2,6,10,13,17,20}},
["2.5"] = {{3,7,11,16,20,24,29,33},{2,5,8,10,13,16}},
["3"]   = {{2,6,10,13,17,20,24,27},{2,4,6,9,11,13}},
["3.5"] = {{2,5,8,11,14,17,20,23},{1,3,5,7,10,12}},
["4"]   = {{2,5,7,10,13,15,18,21},{1,3,5,7,8,10}},
["4.5"] = {{2,4,6,9,11,13,16,18},{1,3,4,6,7,9}},
["5"]   = {{1,4,6,8,10,12,14,16},{1,2,4,5,7,8}},
}

Usage:

local function getMonSize(x,y,scale)
   return screenResolution[scale][1][x],screenResolution[scale][2][y]
end
xValue, yValue = getMonSize(5,3,"1.5")
--Note: remember to put the quote on the scale value

Lupus590, on 09 August 2016 - 12:22 AM said:

http://computercraft...ki/Term.getSize

I know that function… My question is if there is any mathematical formula to calculate the resolution starting from the number of screen horizontally and vertically

So you want to get the resolution based off how many monitors there are? which is kinda pointless as you can do what Lupus590 said..

The_Cat, on 09 August 2016 - 01:08 PM said:

So you want to get the resolution based off how many monitors there are? which is kinda pointless as you can do what Lupus590 said..

I need it because I want to calculate the resolution even without have the monitor connected to the computer.
I think I will create a table with every resolution of every scale

I did this test:

mon = peripheral.wrap("top")

w, h = mon.getSize()

-- Amount the monitor can hold
hMonitor = {6, 7}
wMonitor = {9, 11}

mon.clear()
mon.setBackgroundColor(colors.black)

for i = 1, w do
mon.setCursorPos(i, 1)
mon.write("1")
end

for i = 1, h do
mon.setCursorPos(1, i)
mon.write("2")
end

You can figure out the resolution knowing the amount of pixel can fit where.

The_Cat, on 09 August 2016 - 01:32 PM said:

I did this test:

mon = peripheral.wrap("top")

w, h = mon.getSize()

-- Amount the monitor can hold
hMonitor = {6, 7}
wMonitor = {9, 11}

mon.clear()
mon.setBackgroundColor(colors.black)

for i = 1, w do
mon.setCursorPos(i, 1)
mon.write("1")
end

for i = 1, h do
mon.setCursorPos(1, i)
mon.write("2")
end

You can figure out the resolution knowing the amount of pixel can fit where.

But this unfortunately sill need the monitor to be connected to the computer… :(/> I think I'll create some table to solve this problem, something like this:

monitorResolution = {
    scale05 = {{X values},{Y values}},
    scale10 = {{X values},{Y values}},
    scale15 = {{X values},{Y values}},
    ...
}

Bear in mind that the edge pieces have a different resolution to the middle pieces. You'll need to track those separately.

Well if you know 1 screen width for the edges and non edges you can work it out… For example 3 horizontal 2x9 (edge monitors) = 18 + 11 (1 non edge) == 29 mean the width of 3 monitors is 29… I wrote that program to find out these values.

The_Cat, on 09 August 2016 - 02:10 PM said:

Well if you know 1 screen width for the edges and non edges you can work it out… For example 3 horizontal 2x9 (edge monitors) = 18 + 11 (1 non edge) == 29 mean the width of 3 monitors is 29… I wrote that program to find out these values.

I'll try this method in a moment

The only way I can think of doing this accurately would be to create a huge table:

local monSize = {
  {{7,5},{7,12},{7,19},{7,26},{7,33},{7,40}};
  {{18,5},{18,12},{18,19},{18,26},{18,33},{18,40}};
  {{29,5},{29,12},{29,19},{29,26},{29,33},{29,40}};
  {{39,5},{39,12},{39,19},{39,26},{39,33},{39,40}};
  {{50,5},{50,12},{50,19},{50,26},{50,33},{50,40}};
  {{61,5},{61,12},{61,19},{61,26},{61,33},{61,40}};
  {{71,5},{71,12},{71,19},{71,26},{71,33},{71,40}};
  {{82,5},{82,12},{82,19},{82,26},{82,33},{82,40}};
}
local monSizeTest = monSize[3][2] -- Gets monitor size of 3x2 monitor
monSizeTest[1] -- width of mon size 3x2
monSizeTest[2] -- height of mon size 3x2

Otherwise, you could do it slightly more efficiently with a function:

local monSizeX = {7,18,29,39,50,61,71,82}
local monSizeY = {5,12,19,26,33,40}
function getMonSize(x,y)
  return monSizeX[x],monSizeY[y]
end
local x,y = getMonSize(3,2) -- x = x size of 3x2 y = y size of 3x2

Twijn, on 09 August 2016 - 05:16 PM said:

The only way I can think of doing this accurately would be to create a huge table:

local monSize = {
  {{7,5},{7,12},{7,19},{7,26},{7,33},{7,40}};
  {{18,5},{18,12},{18,19},{18,26},{18,33},{18,40}};
  {{29,5},{29,12},{29,19},{29,26},{29,33},{29,40}};
  {{39,5},{39,12},{39,19},{39,26},{39,33},{39,40}};
  {{50,5},{50,12},{50,19},{50,26},{50,33},{50,40}};
  {{61,5},{61,12},{61,19},{61,26},{61,33},{61,40}};
  {{71,5},{71,12},{71,19},{71,26},{71,33},{71,40}};
  {{82,5},{82,12},{82,19},{82,26},{82,33},{82,40}};
}
local monSizeTest = monSize[3][2] -- Gets monitor size of 3x2 monitor
monSizeTest[1] -- width of mon size 3x2
monSizeTest[2] -- height of mon size 3x2

Otherwise, you could do it slightly more efficiently with a function:

local monSizeX = {7,18,29,39,50,61,71,82}
local monSizeY = {5,12,19,26,33,40}
function getMonSize(x,y)
  return monSizeX[x],monSizeY[y]
end
local x,y = getMonSize(3,2) -- x = x size of 3x2 y = y size of 3x2

I think I'll do it this way

I solved the problem using a big table that involve x and y values and also scales.
To help future users here is the full table:

screenResolution = {
["0,5"] = {{15,36,57,79,100,121,143,164},{10,24,38,52,67,81}},
["1"]   = {{7,18,29,39,50,61,71,82},{5,12,19,26,33,40}},
["1,5"] = {{5,12,19,26,33,40,48,55},{3,8,13,17,22,27}},
["2"]   = {{4,9,14,20,25,30,36,41},{2,6,10,13,17,20}},
["2,5"] = {{3,7,11,16,20,24,29,33},{2,5,8,10,13,16}},
["3"]   = {{2,6,10,13,17,20,24,27},{2,4,6,9,11,13}},
["3,5"] = {{2,5,8,11,14,17,20,23},{1,3,5,7,10,12}},
["4"]   = {{2,5,7,10,13,15,18,21},{1,3,5,7,8,10}},
["4,5"] = {{2,4,6,9,11,13,16,18},{1,3,4,6,7,9}},
["5"]   = {{1,4,6,8,10,12,14,16},{1,2,4,5,7,8}},
}

Usage:

local function getMonSize(x,y,scale)
   return screenResolution[scale][1][x],screenResolution[scale][2][y]
end
xValue, yValue = getMonSize(5,3,"1,5")
--Note: remember to put the quote on the scale value