Help with bundeled output

I'm trying to make a program which when run will send 3 pulses of white color redstone output through a bundled cable.
I haven't coded Lua in a long time, so this should be easy for you guys, but I can't figure it out myself, nor with Google.

Thanks for all help!


My code:

rs.setBundledOutput("back", color.white)
os.sleep(1)
rs.setBundledOutput("back", color.white)
os.sleep(1)
rs.setBundledOutput("back", color.white)
os.sleep(1)
shell.run("clear")
end

close, you just need to clear the output between pulses

rs.setBundledOutput("back", color.white)
os.sleep(0.5)
rs.setBundledOutput("back",0)
os.sleep(0.5)
rs.setBundledOutput("back", color.white)
os.sleep(0.5)
rs.setBundledOutput("back",0)
os.sleep(0.5)
rs.setBundledOutput("back", color.white)
os.sleep(0.5)
rs.setBundledOutput("back",0)

and the end is unneeded

Thank you for the quick help!

I did exactly what you wrote, but i do only get "attempt to index ? (a nil value).

It's colors.white, plural colors not color.

sorry lol, I was just copying and adapting it… made a blind mistake, corrected again

rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)
sleep(0.5)
rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)
sleep(0.5)
rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)

luanub, on 16 August 2012 - 08:24 AM said:

It's colors.white, plural colors not color.

yep, beat me to it

Thank you, it works!

To condense it do:

for cnt = 1,3 do
rs.setBundledOutput("back", colors.white)
sleep(0.5)
rs.setBundledOutput("back",0)
sleep(0.5)
end

A for loop (for varaible = startnumber,endnumber do end)
will go through the stuff in it with the set variable going up one each time.
Useful for doing something a set number of times or doing something for a multitude of numbers.