[Solved][Lua][Error]Parallel.waitForEver():

The program, shown below, never stops, despite i reaching 10.
Note: the receiving turtle is inactive, so no message is received by the code, and x is not pressed.

term.clear()
term.setCursorPos(1,1)
exit = false
exitrpt = false
i = 0
turtlecontrol = {
  send = function()
	repeat
	  i = i + 1
	  rednet.broadcast("intro")
	  print(i)
	until exitrpt or i == 10
  end;
  receive = function()
	eventtype,p1,p2,p3 = os.pullEvent()
	exitrpt = true
	if eventtype == "rednet_message" then
	  print(p2)
	else
	  if eventtype == "char" and p1 == "x" then
		exit = true
	  end
	end
  end;
}
print("Sending...")
parallel.waitForAny(turtlecontrol.send(),turtlecontrol.receive())
if exit == false then
  if exitrpt == false then
	print("Failed")
  end
end

The full output is:

Sending…
1
2
3
4
5
6
7
8
9
10

And the program doesn't end.

You don't have to call the functions, just pass them as parameters:

parallel.waitForAny(turtlecontrol.send, turtlecontrol.receive) -- removed the brackets

Also, the send function never yields, so it won't run at the same time as the receive, so it's pretty pointless to use parallel.

The parallel is necessary to make the program work, as I want the program to continuously send while waiting for an event. With the 2 running in the same code section, the event pull will stop the repeat, and for the 2 to run simultaneously in different code sections, only a parallel can be used. So firstly, what do you mean by yield? and secondly, how could I recode the send function to yield, making the parallel possible?
Removing the brackets seems to have resolved the problem, thanks.