[Lua] [question] simple vertical dig&drop off program using excavate

so im trying to make a simple dig program using the built in excavate program, since excavate digs all the way down and comes back automatically I figure it would make it a whole lot easier to just run excavate then put in programing to unload.
This is what ive got so far

clear
shell.run("excavate" "3")
end

yea… seriously it took me almost 2 hours to figure out that i needed "" .
my problem now is that i cant get the arguement for excavate in i type in

but when i run this it tells me: bios:206: [string "dig"]:3: '='
expected

apart from running excavate i want to add the drop program this is what ive found
end
for dropSlot = 1, 9 do
turtle.select(dropSlot)
turtle.drop()
end

so my first question is is this even possible? and second how do I
get shell.run to work with an argument?/where am i missing an = ?

according to this it should be fine but… still something is wrong

http://www.computerc...h__1#entry13191
using turtle v1.3

You need to seperate the arguments with a comma

shell.run("excavate", "3")

luanub, on 08 September 2012 - 08:46 AM said:

You need to seperate the arguments with a comma

shell.run("excavate", "3")

nope i still get the same error :
to verify:

clear
shell.run("excavate", "3")
end

You dont need that end. Clear isnt defined as a function either, so replace "clear" with "shell.run("clear")

thanks new code is now:
shell.run("clear")
shell.run("excavate", "3")

turtle.turnLeft()
turtle.turnLeft()

for dropSlot = 1, 9 do
turtle.select (dropSlot)
turtle.drop()

end

everything works well, but when i add another
turtle.turnLeft()
turtle.turnLeft()
after the drop the turtle turns around drops, turns around drops again losing half of the items. how do i get him to finish excavating turn around once drop all items and turn around again to repeat?

Put the other turtle.turnLeft() after the end. If you put it before it will turn every time. Since it runs the code 9 times.

shell.run("clear")
shell.run("excavate", "3")
turtle.turnLeft()
turtle.turnLeft()

for dropSlot = 1, 9 do
turtle.select(dropSlot)
turtle.drop()
end

turtle.turnLeft()
turtle.turnLeft()

Also, I took out the space between turtle.selct(dropSlot) since I don't think it should be there. Not sure if it works either way.

thanks works perfectly

actually sorry is there a way to make it repeat 5 times?

print("How many times would you like to run the program?")
local amountOfTimes = tonumber(read())
while amountOfTimes > 0 do

shell.run("clear")
shell.run("excavate", "3")
turtle.turnLeft()
turtle.turnLeft()

for dropSlot = 1, 9 do
turtle.select(dropSlot)
turtle.drop()
end

turtle.turnLeft()
turtle.turnLeft()
amountOfTimes = amountOfTimes - 1
if amountOfTimes == 0 then – not needed
end

i stiched this together from another program with a repeat but it gives me
22: 'end' expected (to close 'while' at line 3)

print("How many times would you like to run the program?")
local amountOfTimes = tonumber(read())
repeat

shell.run("clear")
shell.run("excavate", "3")
turtle.turnLeft()
turtle.turnLeft()

for dropSlot = 1, 9 do
turtle.select(dropSlot)
turtle.drop()
end

turtle.turnLeft()
turtle.turnLeft()
amountOfTimes = amountOfTimes - 1

untill amountOfTimes == 0 then – not needed


modified but now i have 22: = not expected

The error is due to the then in the until statement, it is not needed.

if i do that i get the error 20: 'until' expected (to close 'repeat' at line 3)
i need the untill statement :D/>/>

This is a spelling error. Until only has one L. The line should be:

until amountOfTimes == 0

Lyqyd, on 09 September 2012 - 09:35 AM said:

This is a spelling error. Until only has one L. The line should be:

until amountOfTimes == 0

lmfao thank you that was it
Final program for anyone whos interested:

print("How many times would you like to run the program?")
local amountOfTimes = tonumber(read())
repeat

shell.run("clear")
shell.run("excavate", "3")
turtle.turnLeft()
turtle.turnLeft()

for dropSlot = 1, 9 do
turtle.select(dropSlot)
turtle.drop()
end

turtle.turnLeft()
turtle.turnLeft()
amountOfTimes = amountOfTimes - 1

until amountOfTimes == 0

Ok, so you use a for loop - and a repeat loop which decrements a variable. WHY!

Instead if the repeat do

for i = 1, amountOfTimes do
-- code here
end