[LUA][QUESTION][PROGRAMMING] rs.setBundledOutput...

I want to set the Computer 2 Colored Outputs to one bundled Cable.

I type in
rs.setBundletOuput("back", colors.organge) –> Orange Wire gets powered

Next, I type this
rs.setBundletOuput("back", colors.red) –> Red Wire gets powered , orange wire gets unpowered

—————-

This is what i'm trying

rs.setBundletOuput("back", colors.organge) –> Orange Wire gets powered
rs.setBundletOuput("back", colors.red) –> Red ANDOrange Wire gets powered

How do I have to do this?

Hope it helps!

 
rs.setBundledOutput("back", colors.orange, colors.red)

You are looking for the colors.combine() and colors.subtract() functions. Try this:

rs.setBundledOutput("back",colors.combine(colors.orange)) --orange wire on
rs.setBundledOutput("back",colors.combine(colors.red)) --orange stays on, red also turned on.
rs.setBundledOutput("back",colors.subtract(colors.orange)) --orange wire turned off, red still on
rs.setBundledOutput("back",0) --all colors turned off, no matter what

Hope that helps!

Edit: You can also add multiple colors at a time, by adding more colors in the parenthesis for colors.combine or colors.subtract. Like this:

rs.setBundledOutput("back",colors.combine(colors.red,colors.orange)) --both colors added at the same time.

Matrixmage, on 25 September 2012 - 08:26 PM said:

Hope it helps!

rs.setBundledOutput("back", colors.orange, colors.red)

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Cranium, on 25 September 2012 - 08:27 PM said:

You are looking for the colors.combine() and colors.subtract() functions. Try this:

rs.setBundledOutput("back",colors.combine(colors.orange)) --orange wire on
rs.setBundledOutput("back",colors.combine(colors.red)) --orange stays on, red also turned on.
rs.setBundledOutput("back",colors.subtract(colors.orange)) --orange wire turned off, red still on
rs.setBundledOutput("back",0) --all colors turned off, no matter what

Hope that helps!

Edit: You can also add multiple colors at a time, by adding more colors in the parenthesis for colors.combine or colors.subtract. Like this:

rs.setBundledOutput("back",colors.combine(colors.red,colors.orange)) --both colors added at the same time.

Thanks :P/>/>

Matrixmage, on 25 September 2012 - 08:26 PM said:

Hope it helps!

rs.setBundledOutput("back", colors.orange, colors.red)

Thank you very much!

Cranium, on 25 September 2012 - 08:27 PM said:

You are looking for the colors.combine() and colors.subtract() functions. Try this:

rs.setBundledOutput("back",colors.combine(colors.orange)) --orange wire on
rs.setBundledOutput("back",colors.combine(colors.red)) --orange stays on, red also turned on.
rs.setBundledOutput("back",colors.subtract(colors.orange)) --orange wire turned off, red still on
rs.setBundledOutput("back",0) --all colors turned off, no matter what

Hope that helps!

Edit: You can also add multiple colors at a time, by adding more colors in the parenthesis for colors.combine or colors.subtract. Like this:

rs.setBundledOutput("back",colors.combine(colors.red,colors.orange)) --both colors added at the same time.

Sry.. I tried in Lua Live Editor.. i think thats the problem :$$


rs.setBundledOutput("back",colors.combine(colors.orange)) –orange wire on
rs.setBundledOutput("back",colors.combine(colors.red)) –orange stays on, red also turned on.

use notepad++, it's the best :P/>/>

I agree. Notepad++ is by far my favorite text editor now.