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Hello, I'm attempting to create a program for a tekkit train station. The program I am currently working on is to buy tickets. I have written a basic program using numerical inputs to designate where you want to go.

Its been tested and works fine but i want something a bit more advanced with a menu. I have watched a few tutorials and have a little understanding, but I just cant seem to get it to work.

I was just wondering if anyone can give me a few tips or hints on how to write the program I would like.

The basic program I used is;


shell.run("clear")
term.setCursorPos(1,1)
print("Welcome to the Rim Station")
print("")
print(" Ticket Sales")
print(" Select Ticket")
print(" ")
print("[1] Destination 1")
print("[2] Destination 2")
print("[3] Destination 3")
print("[4] Destination 4")

input = read()

A = "1"
B = "2"
C = "3"
D = "4"
E = "5"
F = "6"
G = "Edit"

if input == A then
shell.run("clear")
term.setCursorPos(1,1)
rs.setBundledOutput("back", 1)
print("Please Insert 1IC into payment shoot")
sleep(4)
print("")
print("Printing, Please Wait")
sleep(27)
shell.run("startup")

elseif input == B then
shell.run("clear")
term.setCursorPos(1,1)
rs.setBundledOutput("back", 16384)
print("Please Insert 1IC into payment shoot")
sleep(4)
print("")
print("Printing, Please Wait")
sleep(27)
shell.run("startup")


elseif input == C then
shell.run("clear")
term.setCursorPos(1,1)
rs.setBundledOutput("back", 64)
print("Please Insert 1IC into payment shoot")
sleep(4)
print("")
print("Printing, Please Wait")
sleep(27)
shell.run("startup")


elseif input == D then
shell.run("clear")
term.setCursorPos(1,1)
rs.setBundledOutput("back", 2048)
print("Please Insert 1IC into payment shoot")
sleep(4)
print("")
print("Printing, Please Wait")
sleep(27)
shell.run("startup")


elseif input == G then
shell.run("click")

else
shell.run("controls")

end

Thanks

Here are a couple little tricks that may help you:

--Make a function for each menu option. start() help() quit()
--These functions cannot take any parameters.
--Assign them to a table similar to this:
menuItems = {[0] = start,help,quit}
--The '[0] =' is both important AND optional depending on your personal preference.
--It starts the indexing at '0' instead of '1'.
--You don't need this, but without it you will require a few extra '+ 1's in some formulas.

--Initialize the position in the menu
local selected = 0
while true do
 local evt = {os.pullEvent()}   --The { } packs return values into a table. you can use ' local evt,k = os.pullEvent()' instead.
 if evt[1] == "key" then
  if evt[2] == UPARROW then   --I don't remember the Key Code for the UPARROW
   selected = (selected - 1) % (#menuItems + 1)   --The '#' gives the number of items in the table. the Modular division keeps us from going out of bounds.
  elseif evt[2] == DOWNARROW then
   selected = (selected + 1) % (#menuItems + 1)
  elseif evt[2] == ENTERKEY
   menuItems[selected]()   --This will call the function associated with the selected item.
  end
 end
end

…I hope I didn't make any errors in the code above…

Another thing that you can do, that would probably be neater (My opinion) is use os.pullEvent("key"). What this does, is wait for an input to do something; an example.

repeat -- Repeat just incase of an invalid key; like of someone presses key "A" then, have it do nothing. (That would exit the program.)
   event, key = os.pullEvent("key")
   os.sleep(0.1)
until key == 2 or key == 3 or key == 4 or key == 5 or key == 6 -- Know that this is the key's ID. Not the key itself. See the link for the ID's below.
if key == 2 then
   -- If someone presses 1.
elseif key == 3
   -- If someone presses 2.
elseif key == 4
   -- If someone presses 3.
elseif key == 5.
   -- If someone presses 4.
elseif key == 6
   -- If someone presses 5.
end

Find the key IDs here.

I hope that this helps!

By the way, os.pullEvent() can do many more things, so you may want to check that out on the wiki.