Strange Problem

So I really don't know why this is happening. All of my code works fine, except for one part that should work anyway. (My problem is toward the end)
edit: Made my description of problem clearer

 --Just a simple function
function clearall()
term.clear()
term.setCursorPos(1,1)
end

test = 0
diskside = ""

--Just checks to see if there is a disk
check = fs.exists("disk")
if check ~= true then
test = 1
end

--The part that actually  moves the programs
while test ~= 1 do
clearall()
print("What operation?")
print("download/upload")
local choice = io.read()
if choice == "download" then
test = 1
end
if choice == "upload" then
test = 1
end
clearall()

if choice == "download" then
local ondisk = fs.list("disk")
for i=1, #ondisk do
local current = fs.combine("disk",ondisk[i])
fs.delete(ondisk[i])
fs.copy(current,ondisk[i])
end
else

if choice == "upload" then
local oncomp = fs.list("")
for i=1, #oncomp do
local current = fs.combine("disk",oncomp[i])
if (oncomp[i] ~= "rom") and
   (oncomp[i] ~= "disk") then
fs.delete(current)
fs.copy(oncomp[i],current)
end
end
end

end

end

if check == true then
textutils.slowPrint("Working...")
sleep(1)
print("")
print("Done")

--The part I'm having trouble with: with this code, it is not ejecting the disk
--Note: the table "side" is defined by a program that runs at startup and gives all the different sides as strings.
-- Also, when this runs, choice is supposed to either equal "upload" or "download" or else it wouldn't have broken the while
--Now, the strange thing is, if I take out the if choice == "upload" then, and the end that follows
--then it does what its supposed to do, but like this, it dosen't do anything
if choice == "upload" then
for i=#side, 1, -1 do
diskcheck = disk.isPresent(side[i])
if diskcheck == true then
diskside = side[i]
end
end
disk.eject(diskside)
end

else
print("No disk")
end

Where do you define 'choice'. What does the error say?

Its not an error, it just seems like it skips the code.
choice is defined towards the top.

local choice = io.read()

Well actually nevermind.

I just tried taking out the local from "local choice" and now it works.
What exactly does local mean anyway?

civilwargeeky, on 14 October 2012 - 04:33 AM said:

Its not an error, it just seems like it skips the code.
choice is defined towards the top.

local choice = io.read()

Oh right, didn't see that lol. I can't read codes that aren't indented :)/>/>

Change this:

local choice = io.read()

To:

local choice = read()

I'm pretty sure that Lua in CC won't take io.read().

civilwargeeky, on 14 October 2012 - 04:52 AM said:

What exactly does local mean anyway?

I think it means that the variable will only be there within the length the program is open. A global variable stays around unless you reset the computer. That's at least what I heard.

you sould also combine if and else statements
elseif <expression> then

brett122798, on 14 October 2012 - 08:23 AM said:

Change this:

local choice = io.read()

To:

local choice = read()

I'm pretty sure that Lua in CC won't take io.read().

It does

sIdEkIcK_, on 14 October 2012 - 11:32 AM said:

brett122798, on 14 October 2012 - 08:23 AM said:

Change this:

local choice = io.read()

To:

local choice = read()

I'm pretty sure that Lua in CC won't take io.read().

It does

really? last time i checked io.read wasnt compatible with term
unless the devs changed it, idk

PixelToast, on 14 October 2012 - 06:25 PM said:

sIdEkIcK_, on 14 October 2012 - 11:32 AM said:

brett122798, on 14 October 2012 - 08:23 AM said:

Change this:

local choice = io.read()

To:

local choice = read()

I'm pretty sure that Lua in CC won't take io.read().

It does

really? last time i checked io.read wasnt compatible with term
unless the devs changed it, idk

io.read() uses read(), and has for probably most of the life of the mod. It works just fine.