LUA error index lua 24 method must be called with a colon

if menustatus >= 4 then

The greater than sign must come before the equals sign.

Are you sure this is working?

ChunLing, on 21 October 2012 - 04:28 AM said:

Are you sure this is working?

Why is there something else wrong?

That is what I was asking.

Let me see

C'mon no errors but no menu shows up.
new menu……

blue = Color.new(0, 50, 175)
white = Color.new(255,255,255)

ms = 1
mms = 5

oldpad = Controls.read()

while true do
screen:clear()
pad = Controls.read()

if pad:up() and oldpad:up() ~= pad:up() then
ms = ms - 1
end
if pad:down() and oldpad:down() ~= pad:down() then
ms = ms + 1
end
if ms > mms then
ms = 1
elseif ms <= 0 then
ms = mms
end

mc = { white,white,white,white,white }
mc[ms] = blue
screen:print(98,107,"Game",mc[1])
screen:print(98,117,"Opti on 2",mc[2])
screen:print(98,127,"Opti on 3",mc[3])
screen:print(98,137,"Opti on 4",mc[4])
screen:print(98,147,"Opti on 5",mc[5])

if pad:cross() and not oldpad:cross() and ms == 1 then
dofile("Game.lua")
end
if pad:cross() and not oldpad:cross() and ms == 2 then
–Paste code that happens when X is pressed over option 2
end
if pad:cross() and not oldpad:cross() and ms == 3 then
–Paste code that happens when X is pressed over option 3
end
if pad:cross() and not oldpad:cross() and ms == 4 then
–Paste code that happens when X is pressed over option 4
end
if pad:cross() and not oldpad:cross() and ms == 5 then
break
end

if ms <= 0 then
ms = 5
end

if ms >= 6 then
ms = 1
end

screen.waitVblankStart()
screen.flip()
oldpad = pad
end

When I click option 5 it says error:(null)
What its sposed to do is break (stop) the entire code and exit game how do i fix?

Using break takes you out of the innermost current loop. The innermost current loop in this case is the while true do end, so you skip to the bottom of the program and lua can't find any more lines of code there. Perhaps you should use return false or something.

ChunLing, on 23 October 2012 - 11:43 PM said:

Using break takes you out of the innermost current loop. The innermost current loop in this case is the while true do end, so you skip to the bottom of the program and lua can't find any more lines of code there. Perhaps you should use return false or something.

I'll try, but would this be right?
if pad:cross() and not oldpad:cross() and ms == 1 then
dofile("Game.lua")

end
If I wanted to load a game lua file up?

Not too familiar with the Controls API which you're using. So can't say for sure whether any of that works. But dofile(filename) should work as long as the filename is right and the file is lua.

i respect everyone here it has a great lasting community that words will not describe

Error no loop to break near end what now?
–Created by dragonxtamer596

–On the 10/18/12


Room_width = 480
Room_height = 272
player1x =240
player1y =136
—Load Sprites —
background =Image.load ("images/Background.PNG")
player1=Image.load("images/Player1.PNG")

——functions
function checkcontrols()
pad = Controls.read()
if pad:start() then
exitgame = 1
end
if pad:right() then
player1x = player1x -2
end
if pad:left() then
player1x = player1x +2
end
if pad:up() then
player1y = player1y - 2
end
if pad:down() then
player1y = player1y +2
end
end
function drawall()
screen:blit (0,0,background)
screen:blit(player1x,player1y,player1)
screen.waitVblankStart()
screen.flip()
end

– MAIN LOOP
while true do
end

checkcontrols()
drawall()
if pad:start() == 1 then
break
end

You have while true do end as your main loop, then some code sticking out at the end of the file. Get rid of the end right after the while true do.

In fact, if you break out of it after once through like that, you may as well just get rid of the loop, and the break altogether.

Also I'm making a random number generator
error index lua 24 method must be called with a colon
code what do i do?

– My Second Lua Program
– Author: Dragonxtamer596

red = Color.new(255, 0, 0)

function checkcontrols()
pad = Controls.read()
if pad:start() then
end
exitgame = 1
end

local choice = math.random(1, 3) –Chooses a random number between 1 and 3.

if choice == 1 then
screen.print(200, 100, "1", red)
end

if choice == 2 then
screen.print(200, 100, "2", red)
end

if choice == 3 then
screen.print(200, 100, "3", red)
end

screen.flip()
while true do
screen.waitVblankStart()
end

checkcontrols()
drawall()
if pad:start() == 1 then
end
while true do
break
end

Please put your code in

[code] -- code here [/code*] (without the *)

tags and state what you need help with and / or what your error is. This is very difficult too read.