18 posts
Posted 29 October 2012 - 02:41 PM
I'm having trouble getting this program to work. It keeps giving me an error
'then' expected on line 14, it's there and it just won't run.
Spoiler
tBoard1={" ";" ";" ";" ";" ";}
tBoard2={" ";" ";" ";" ";" ";}
tHeader={1;2;3;4;5;}
sSColumn=0
sSRow=0
sGColumn=0
sGrow=0
print([[ Enter starting point by typing in the column number first. ]])
sSColumn=read()
if tonumber(sSColumn) = nil then
print([[You entered an invaild column number.]])
else
while true do
print([[now enter the row number.]])
sSRow=[read()]
if tonumber(sSRow) = nil then --right here
print([[you entered an invaild row number. try again.]])
end
break
end
end
print([[ Enter goal point by typing in the column number first. ]])
sGColumn=read()
if tonumber(sGColumn) = nil then
print([[You entered an invaild column number.]])
else
while true do
print([[now enter the row number.]])
sGRow=[read()]
if tonumber(sGRow) = nil then
print([[you entered an invaild row number. try again.]])
end
break
end
end
if sSColumn=sGColumn or sSRow=sGRow then
print([[Error]])
restart()
end
if sSRow = 1 then
tBoard1[sSColumn] = "S"
else
tBoard2[sSColumn] = "S"
end
if sGRow = 1 then
tBoard1[sGColumn] = "G"
else
tBoard2[sGColumn] = "G"
end
print(tHeader)
print(tBoard1)
print(tBoard2)
30 posts
Location
Brazil
Posted 29 October 2012 - 02:48 PM
Instead of
if tonumber(sSColumn) = nil then
It's supposed to be
if tonumber(sSColumn) == nil then
This applies to every if.
8543 posts
Posted 29 October 2012 - 02:50 PM
Not sure what change the above poster was suggesting. All equality comparisons need the symbol ==, not just =.
18 posts
Posted 29 October 2012 - 03:06 PM
Now I'm having trouble making the tables to display
I tried using (" ") (, ,) (' ') ( ) ([ ])(… …) (.. ..) and I'm getting error on line 68 for unexpected symbol
8543 posts
Posted 29 October 2012 - 04:41 PM
You can't just tell it to print the table. You either have to use one of the table functions to concatenate the table into a single string or you have to print individual values from it.
2088 posts
Location
South Africa
Posted 29 October 2012 - 05:17 PM
Yeah, you will have to use a for loop to display what is in the table
table = {"This","table","is","being","printed"}
for i=1,#table do
print(table[i])
end
Result:
Spoiler
This
table
is
being
printedOr to make it into one line
table = {"This","table","is","being","printed"}
for i=1,#table do
write(table[i].." ")
end
Result:
Spoiler
This table is being printed
18 posts
Posted 29 October 2012 - 05:26 PM
Yeah, you will have to use a for loop to display what is in the table
table = {"This","table","is","being","printed"}
for i=1,#table do
print(table[i])
end
Result:
Spoiler
This
table
is
being
printedOr to make it into one line
table = {"This","table","is","being","printed"}
for i=1,#table do
write(table[i].." ")
end
Result:
Spoiler
This table is being printed
Thanks! I was looking that up awhile ago :P/>/>