Is there an equivalent for $PATH in CraftOs?

So I got into cc recently and I'm having a blast so far, but I'm wondering: Is there a way to execute programs without either traversing the directory tree or specifying the path?
Ideally I'd like to have a list of directories that the shell checks for an executable by the given name.

I could adapt loadreq to that; in fact I'm gonna do it.

Ok, updated the loadreq with a simple function and some changes that allow to use it to run files as normally.
E.g.:

---runs filepath path with args ... using the same rules as @require for determining the globs to uses
--e.g.
--[[
os.loadAPI('APIS/loadreq')
loadreq.vars.paths=loadreq.vars.paths..';myFolder'
--or
REQUIRE_PATH='myFolder'
--ect
loadreq.run_lua('subFolder/subsubFolder/myFile.lua',arg1,arg2,...)
]]

use the command shell.setPath(dirs separated by ';'s ) it is the equivalent of %path% in cmd

local function add(dir)
  if fs.exists(dir) and fs.iDir(dir) then
	shell.setPath(shell.getPath..';'..shell.resolve(dir))
  end
end

KaoS, on 13 December 2012 - 02:30 AM said:

snip

How dumb of me to misinterpret the whole thing.. :blink:/>

CoolisTheName007, on 13 December 2012 - 05:39 AM said:

snip

we all derp. chilled stuff

KaoS, on 13 December 2012 - 02:30 AM said:

use the command shell.setPath(dirs separated by ';'s ) it is the equivalent of %path% in cmd

local function add(dir)
  if fs.exists(dir) and fs.iDir(dir) then
	shell.setPath(shell.getPath..';'..shell.resolve(dir))
  end
end

Just what I was looking for, thank you!

CoolisTheName007, on 13 December 2012 - 05:39 AM said:

[…]
How dumb of me to misinterpret the whole thing.. :blink:/>

After all we're only humans == derpy :~)
Thanks for trying to help me out.