Program Errors Like <eof> expected

Here is my program:

function doorTrue()
print("Opening Door")
redstone.setOutput("left",true)
sleep(7)
end
function doorFalse()
print("Closing Door")
redstone.setOutput("left",false")
end
on == true
off == false
write "On/Off: "
if input = true then doorTrue()
if input = false then doorFalse()
end

Now, when I try to run this program, it gives me a [string "door"]:13: 'then' expected. I have no idea what I have to do there. Then sometimes, it gives me an error saying [string "door"]:10: "=" expected, but I know that I need on to have to value of true, so I don't change it. And, finally, I sometimes get the error [string "door"]:5: <eof> expected. I don't even know what eof means. Can anyone help?

You have comparison and assignment backwards. Where you have ==, it should be = and where you have =, it should be ==.

Using = is setting a variable
Using == or === is comparing a variable to another variable.

You either need another 'end' or a 'elseif' in place of the second 'if'

You are checking the 'input' variable but never declaring it

The write function needs (), this isn't PHP.

EDIT: Damn you ninja posts…

function doorTrue()
print("Opening Door")
redstone.setOutput("left", true)
sleep(7)
end
function doorFalse()
print("Closing Door")
redstone.setOutput("left",false")
end
input = read()
write ("On/Off: ")
if input == "On" then
doorTrue()
elfeif input == "Off" then
doorFalse()
end

Your code should work fine now, try that^

zekesonxx, on 04 January 2013 - 11:18 AM said:

Using = is setting a variable
Using == or === is comparing a variable to another variable.

You either need another 'end' or a 'elseif' in place of the second 'if'

You are checking the 'input' variable but never declaring it

The write function needs (), this isn't PHP.

EDIT: Damn you ninja posts…

You ninja posted me brah.

zekesonxx, on 04 January 2013 - 11:18 AM said:

The write function needs (), this isn't PHP.

It doesn't need the ()