help for bundled cable

Hello, everybody!

I want to do something with bundled cable.
I want to do like a flip-flop for activate/desactivate my lamps, with one program in the yellow cable I do like this:

if redstone.getBundledOutput("back", colors.yellow) == false then
redstone.setBundledOutput("back", colors.yellow, true)
else
redstone.setBundledOutput("back", colors.yellow, false)
end

and when I launch the program it returns me :

lamp:1: attempt to index ? (a nil value)

so I don't know what it is
if you know how to do or how to fix it.

Thanks

PS: I'm frensh so sorry for my bad english :@

Instead of

if redstone.getBundledOutput("back", colors.yellow) == false then

try using

if redstone.testBundledInput("back", colours.yellow) then

When in doubt, check the wiki :)/>

Ok, first of all, thank you. I've do this and I add something like this:

if redstone.testBundledInput("back", colors.yellow) then
if input == "false" then
redstone.setBundledOutput("back", colors.yellow, true)
else
redstone.setBundledOutput("back", colors.yellow, false)
end
end

and it returns me :

lamp:5: Expected string, number

the way you use "redstone.setBundledOutput()" is like this
redstone.setBundledOutput(side,color)
there is no boolean as an argument (true or false)
so all of them should look like: redstone.setBundledOutput("back",colors.yellow)
to turn one off you do redstone.setBundledOutput("back",0)

you could do this if you KNOW that yellow is on by doing

rs.setBundledOutput( "back", rs.getBundledOutput( "back" ) - colors.yellow )

Ok but this

redstone.setBundledOutput("back",0)

will not reset all of the colors ?

and i don't know what do you mean TheOriginalBIT

redstone.setBundledOutput( "back", 0 ) will turn them all off…

what I meant is this:

local input = read()

if input == "turn off yellow" and rs.testBundledInput( "back", colors.yellow ) then
  rs.setBundledOutput( "back", rs.getBundledInput( "back" ) - colors.yellow )
else
  print( "Yellow isn't on")
end

That will turn off yellow if it is on, but leave all the others on…

Ok and there is a way to turn them off individually ?

read edit

Ok, but this don't turn on if it's off and vice-versa ?

try this out:

local input = read()

if input == "toggle yellow" then
  local num = ( rs.testBundledInput( "back", colors.yellow ) and -colors.yellow or colors.yellow )
  rs.setBundledOutput( "back", rs.getBundledInput( "back" ) + num  )
  print( "Yellow is now "..( rs.testBundledInput( "back", colors.yellow ) and "on" or "off" )
end

this should set the output based on the if yellow is on or off…

and now it returns me a:

bios:338: [string "light"]:6: unexpected symbol

and I've the exact same code at line 6

sorry missed a closing ) at the end of line 6

that means I must have:

print( "Yellow is now "..( rs.testBundledInput( "back", colors.yellow ) and "on" or "off" ))

????

yes that should be fine now…

it returns me the exact same error

odd… give me a bit, have to go do some house work then I'll open up Minecraft and test it for you…

ok so I just tested this code and it works perfectly

local function toggleColor( c )
	if redstone.testBundledInput( "back", c ) then
		rs.setBundledOutput( "back", rs.getBundledInput( "back" ) - c  )
	else
		rs.setBundledOutput( "back", rs.getBundledInput( "back" ) + c  )
	end

	print( c.." toggled is now "..( rs.testBundledInput( "back", c ) and "off" or "on" ) )
end

what I used to test it

while true do
	local input = read()

	if input == "off" then
		rs.setBundledOutput( "back", 0 )
	elseif tonumber( input ) > 1 and tonumber( input ) < 16 then
		toggleColor( 2 ^ tonumber( input ) )
	end
end

EDIT: Or here is similar as what I posted in replies above, functionally its no different than above example code, just smaller in size

local function toggleColor( c )
  rs.setBundledOutput( "back", rs.getBundledInput( "back" ) + ( rs.testBundledInput( "back", c ) and -c or c )  )
  print( c.." toggled is now "..( rs.testBundledInput( "back", c ) and "off" or "on" ) )
end

Ok I will test it, thanks